Optimal. Leaf size=196 \[ \frac{b \left (30 a^2 c^2-20 a b^2 c+3 b^4\right ) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{c^4 \left (b^2-4 a c\right )^{3/2}}+\frac{\left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 c^4}-\frac{b x \left (3 b^2-11 a c\right )}{c^3 \left (b^2-4 a c\right )}+\frac{x^2 \left (3 b^2-8 a c\right )}{2 c^2 \left (b^2-4 a c\right )}-\frac{b x^3}{c \left (b^2-4 a c\right )}+\frac{x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )} \]
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Rubi [A] time = 0.439333, antiderivative size = 196, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 7, integrand size = 16, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.438 \[ \frac{b \left (30 a^2 c^2-20 a b^2 c+3 b^4\right ) \tanh ^{-1}\left (\frac{b+2 c x}{\sqrt{b^2-4 a c}}\right )}{c^4 \left (b^2-4 a c\right )^{3/2}}+\frac{\left (3 b^2-2 a c\right ) \log \left (a+b x+c x^2\right )}{2 c^4}-\frac{b x \left (3 b^2-11 a c\right )}{c^3 \left (b^2-4 a c\right )}+\frac{x^2 \left (3 b^2-8 a c\right )}{2 c^2 \left (b^2-4 a c\right )}-\frac{b x^3}{c \left (b^2-4 a c\right )}+\frac{x^4 (2 a+b x)}{\left (b^2-4 a c\right ) \left (a+b x+c x^2\right )} \]
Antiderivative was successfully verified.
[In] Int[x/(c + a/x^2 + b/x)^2,x]
[Out]
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Rubi in Sympy [F] time = 0., size = 0, normalized size = 0. \[ - \frac{b x^{3}}{c \left (- 4 a c + b^{2}\right )} + \frac{b \left (30 a^{2} c^{2} - 20 a b^{2} c + 3 b^{4}\right ) \operatorname{atanh}{\left (\frac{b + 2 c x}{\sqrt{- 4 a c + b^{2}}} \right )}}{c^{4} \left (- 4 a c + b^{2}\right )^{\frac{3}{2}}} + \frac{x^{4} \left (2 a + b x\right )}{\left (- 4 a c + b^{2}\right ) \left (a + b x + c x^{2}\right )} + \frac{\left (- 8 a c + 3 b^{2}\right ) \int x\, dx}{c^{2} \left (- 4 a c + b^{2}\right )} - \frac{\left (- 11 a c + 3 b^{2}\right ) \int b\, dx}{c^{3} \left (- 4 a c + b^{2}\right )} + \frac{\left (- 2 a c + 3 b^{2}\right ) \log{\left (a + b x + c x^{2} \right )}}{2 c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(x/(c+a/x**2+b/x)**2,x)
[Out]
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Mathematica [A] time = 0.349643, size = 163, normalized size = 0.83 \[ \frac{\frac{2 b \left (30 a^2 c^2-20 a b^2 c+3 b^4\right ) \tan ^{-1}\left (\frac{b+2 c x}{\sqrt{4 a c-b^2}}\right )}{\left (4 a c-b^2\right )^{3/2}}+\frac{2 \left (2 a^3 c^2+a^2 b c (5 c x-4 b)+a b^3 (b-5 c x)+b^5 x\right )}{\left (b^2-4 a c\right ) (a+x (b+c x))}+\left (3 b^2-2 a c\right ) \log (a+x (b+c x))-4 b c x+c^2 x^2}{2 c^4} \]
Antiderivative was successfully verified.
[In] Integrate[x/(c + a/x^2 + b/x)^2,x]
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Maple [B] time = 0.019, size = 662, normalized size = 3.4 \[{\frac{{x}^{2}}{2\,{c}^{2}}}-2\,{\frac{bx}{{c}^{3}}}-5\,{\frac{bx{a}^{2}}{{c}^{2} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}+5\,{\frac{{b}^{3}xa}{{c}^{3} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}-{\frac{{b}^{5}x}{{c}^{4} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}-2\,{\frac{{a}^{3}}{{c}^{2} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}+4\,{\frac{{a}^{2}{b}^{2}}{{c}^{3} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}-{\frac{a{b}^{4}}{{c}^{4} \left ( c{x}^{2}+bx+a \right ) \left ( 4\,ac-{b}^{2} \right ) }}-4\,{\frac{\ln \left ( \left ( 4\,ac-{b}^{2} \right ) \left ( c{x}^{2}+bx+a \right ) \right ){a}^{2}}{ \left ( 4\,ac-{b}^{2} \right ){c}^{2}}}+7\,{\frac{\ln \left ( \left ( 4\,ac-{b}^{2} \right ) \left ( c{x}^{2}+bx+a \right ) \right ) a{b}^{2}}{{c}^{3} \left ( 4\,ac-{b}^{2} \right ) }}-{\frac{3\,\ln \left ( \left ( 4\,ac-{b}^{2} \right ) \left ( c{x}^{2}+bx+a \right ) \right ){b}^{4}}{2\,{c}^{4} \left ( 4\,ac-{b}^{2} \right ) }}+30\,{\frac{{a}^{2}b}{{c}^{2}\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}\arctan \left ({\frac{2\, \left ( 4\,ac-{b}^{2} \right ) cx+ \left ( 4\,ac-{b}^{2} \right ) b}{\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}} \right ) }-20\,{\frac{a{b}^{3}}{{c}^{3}\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}\arctan \left ({\frac{2\, \left ( 4\,ac-{b}^{2} \right ) cx+ \left ( 4\,ac-{b}^{2} \right ) b}{\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}} \right ) }+3\,{\frac{{b}^{5}}{{c}^{4}\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}\arctan \left ({\frac{2\, \left ( 4\,ac-{b}^{2} \right ) cx+ \left ( 4\,ac-{b}^{2} \right ) b}{\sqrt{64\,{a}^{3}{c}^{3}-48\,{a}^{2}{b}^{2}{c}^{2}+12\,a{b}^{4}c-{b}^{6}}}} \right ) } \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(x/(c+a/x^2+b/x)^2,x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \text{Exception raised: ValueError} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x/(c + b/x + a/x^2)^2,x, algorithm="maxima")
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Fricas [A] time = 0.270392, size = 1, normalized size = 0.01 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x/(c + b/x + a/x^2)^2,x, algorithm="fricas")
[Out]
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Sympy [A] time = 7.77928, size = 1012, normalized size = 5.16 \[ \text{result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x/(c+a/x**2+b/x)**2,x)
[Out]
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GIAC/XCAS [A] time = 0.291716, size = 254, normalized size = 1.3 \[ -\frac{{\left (3 \, b^{5} - 20 \, a b^{3} c + 30 \, a^{2} b c^{2}\right )} \arctan \left (\frac{2 \, c x + b}{\sqrt{-b^{2} + 4 \, a c}}\right )}{{\left (b^{2} c^{4} - 4 \, a c^{5}\right )} \sqrt{-b^{2} + 4 \, a c}} + \frac{{\left (3 \, b^{2} - 2 \, a c\right )}{\rm ln}\left (c x^{2} + b x + a\right )}{2 \, c^{4}} + \frac{c^{2} x^{2} - 4 \, b c x}{2 \, c^{4}} + \frac{a b^{4} - 4 \, a^{2} b^{2} c + 2 \, a^{3} c^{2} +{\left (b^{5} - 5 \, a b^{3} c + 5 \, a^{2} b c^{2}\right )} x}{{\left (c x^{2} + b x + a\right )}{\left (b^{2} - 4 \, a c\right )} c^{4}} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(x/(c + b/x + a/x^2)^2,x, algorithm="giac")
[Out]